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如图1所示为验证动量守恒的实验装置,气垫导轨置于水平桌面上,G1和G2为两个光电门,A、B均为弹性滑块,质量分别为mA、mB,且选择mA大于mB,两遮光片沿运动方向的宽度均为d,实验过程如下; (...
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高三下学期物理《》真题及答案
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某同学利用打点计时器和气垫导轨做验证动量守恒定律的实验.气垫导轨装置如图a所示所用的气垫导轨装置由导
某同学利用打点计时器和气垫导轨做验证动量守恒定律的实验.气垫导轨装置如图13-1-10a所示所用的气
气垫导轨是利用气泵使带孔的导轨与滑块之间形成气垫使滑块悬浮在导轨上滑块在导轨上的运动可视为没有摩擦.
气垫导轨是常用的一种实验仪器它是利用气泵使带孔的导轨与滑块之间形成气垫使滑块悬浮在导轨上滑块在导轨上
气垫导轨是常用的一种实验仪器它是利用气泵使带孔的导轨与滑块之间形成气垫使滑块悬浮在导轨上滑块在导轨上
如图为实验室常用的气垫导轨验证动量守恒的装置.两带有等宽遮光条的滑块A.和B.质量分别为mA.mB.
利用气垫导轨验证机械能守恒定律实验装置示意图如图1所示实验步骤A.将气垫导轨放在水平桌面上桌面高度不
气垫导轨是常用的一种实验仪器它是利用气泵使带孔的导轨与滑块之间形成气垫使滑块悬浮在导轨上滑块在导轨上
8分气垫导轨是常用的一种实验仪器它是利用气泵使带孔的导轨与滑块之间形成气垫使滑块悬浮在导轨上滑块在导
6分如图所示气垫导轨是常用的一种实验仪器它是利用气泵使带孔的导轨与滑块之间形成气垫使滑块悬浮在导轨上
利用气垫导轨验证机械能守恒定律实验装置示意图如图1所示实验步骤A.将气垫导轨放在水平桌面上桌面高度不
某同学利用打点计时器和气垫导轨做验证动量守恒定律的实验气垫导轨装置由导轨滑块弹射架等组成如图a所示实
某同学利用打点计时器和气垫导轨做验证动量守恒定律的实验气垫导轨装置如图甲所示所用的气垫导轨装置由导轨
利用气垫导轨验证机械能守恒定律实验装置如图甲所示.水平桌面上固定一倾斜的气垫导轨导轨上A点放置带有长
气垫导轨是利用气泵使带孔的导轨与滑块之间形成气垫使滑块悬浮在导轨上滑块在导轨上运动时可不计摩擦现用带
气垫导轨是常用的一种实验器材它是利用气泵在带孔的导轨和滑块之间形成气垫使滑块悬浮在导轨上滑块在导轨上
利用气垫导轨验证机械能守恒定律.实验装置示意图如图1所示实验步骤A.将气垫导轨放在水平桌面上桌面高度
气垫导轨是常用的一种实验仪器它是利用气泵使带孔的导轨与滑块之间形成气垫使滑块悬浮有导轨上滑块在导轨上
如图为实验室常用的气垫导轨验证动量守恒的装置.两带有等宽遮光条的滑块A.和B.质量分别为mAmB在A
利用气垫导轨验证机械能守恒定律实验装置示意图如图1所示1实验步骤①将气垫导轨放在水平桌面上桌面高度不
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在正方体ABCD﹣A1B1C1D1中E为棱CD上一点且CE=2DEF为棱AA1的中点且平面BEF与DD1交于点G则B1G与平面ABCD所成角的正切值为
设F1F2分别是离心率为的椭圆E=1a>b>0的左右焦点经过点F2且与x轴垂直的直线被椭圆截得的弦长为.1求椭圆E的方程2设直线ly=x+m与椭圆E交于AB两点线段AB的垂直平分线交x轴点P当m变化时求△PAB面积的最大值.
30分Stevewasaseventhgraderabigboylookingmorelikeateenagerthana12﹣year﹣old.Yethewentunnoticed﹣﹣hehadbeen1everyexaminationsincefirstgrade一untilMissWilma. Inthemiddleofthefirstsemesterofschooltheentireseventhgradewas2forbasicskills. YoualldidprettywellMissWilmatoldtheclassaftergoingoverthe3.exceptforoneboy.Andit4myhearttotellyouthisbut..she5thesmartestboyintheseventhgradeisfailingmyclass.Steve6hiseyesandcarefullyexaminedhisfingertips. AfterthatStevestillwouldn'tdohishomework.EvenifMissWilma7punishedhimheremained8 Steveplease!Icareaboutyou! 9Stevegotit!SomeoneCARESABOUTME?! OneMondayacoupleofweekslaterMissWilmagavea10ontheweekendhomework.Steve11throughthetestandwasthefirsttohandinhispaper.Withalookof12MissWilma1ookhispaperandbegantolookitover. MissWilma'sfacewasin13shock!SheglancedupatStevethen14then up.Thesmartestboyintheseventhgradehadjustpassedhisfirsttest! FromthatmomentnothingwasthesameforSteve.Hediscoveredthatnotonlycouldherememberandunderstand15buthecouldtranslatewhathelearnedintohislife.Hebecame16 AfterhighschoolSteveenlistedintheNavyandhehadan17militarycareer.Duringhisnavalyearsheinspiredmanyyoungpeoplewhomightnothave18themselveswithouthim. A19tookplacewithintheheartofaboyallbecauseofoneteacherwho20. 1A.missing B.failing C.passing D.skipping 2A.tested B.classified C.separated D.dismissed 3A.questions B.effects C.lessons D.results 4A.fills B.presses C.breaks D.destroys 5A.shouted B.hesitated C.interrupted D.laughed 6A.dropped Braised C.covered D.closed 7A.strangely B.steadily C.severely D.secretly 8A.helpless B.stubbom C.flexible D.crazy 9A.Commonly B.Unwillingly C.Particularly D.Suddenly 10A.quiz B.chance C.speech D.presentation 11A.slept B.looked C.lived D.hurried 12A.disppointment B.surprise C.satisfaction D.inspiration 13A.btter B.total C.precious D.ridiculous 14A.down B.away C.out D.back 15A.homework B.grades C.knowledge D.subjccts 16A.outstanding B.lazy C.rough D.troublesome 17A.tiring B.ordinary C.hardworking D.successful 18A.reliedon B.lookedafter C.turnedto D.believedin 19A.competition B.choice C.change D.campaign 20A.waited B.listened C.wished D.cared
设集合A={x|x+1≤3}B={x|4﹣x2≤0}则A∩B=
从某校高三上学期期末数学考试成绩中随机抽取了60名学生的成绩得到如图所示的频率分布直方图 1根据频率分布直方图估计该校高三学生本次数学考试的平均分 2若用分层抽样的方法从分数在[3050和[130150]的学生中共抽取6人该6人中成绩在[130150]的有几人 3在2中抽取的6人中随机抽取2人求分数在[3050和[130150]各1人的概率.
已知双曲线的左右焦点分别为F1F2若双曲线的渐近线上存在点P使得|PF1|=2|PF2|则双曲线C的离心率的取值范围是.
某工厂一年中各月份的收入支出情况的统计如图所示下列说法中错误的是 注结余=收入﹣支出
已知函数fx=|x+2a|a∈R. 1当a=1时解不等式fx+|x﹣a|≤5 2若fx+|x﹣1|≤2的解集包含[12]求a的取值范围.
WhenshefirststartedlearningabouttheclimatechangefromoneofhereldersFawnSharpwasinvitedonahelicopterflightovertheOlympicMountainstosurveytheMountAndersonglacier冰川.Buttheglacierwasgonemeltedbythewarmingclimate.Sharphadadeepsenseoflosswhenshediscoveredtheglacierwasn'tthereanymore. Lossisagrowingissueforpeopleworkingandlivingonthefrontlinesofclimatechange.AndthatgaveJenniferWrenAtkinsonafll﹣timelecturerattheUniversityofWashingtonBothellUSanideaforaclass. ThistermshetaughtstudentsontheBothellcampusaboulthecmotionalburdensofenvironmentalstudy.SheusedtheexperiencesofNaliveAmericantribes部落scientistsandactivistsandaskedher24studentstofacetherealitythatthereisnoeasyfix﹣﹣thatthisissuchanintractableproblemthatthey'regoingtobedealingwithitfortherestoftheirlives. StudentCodyDillonusedtobeaclimatescienceskeptic怀疑论者.Thenhedidhisownreadingandresearchandchangedhismind. Dillonwasn'tgoingintoenvironmentalwork﹣﹣hewasacomputer﹣sciencemajor.Yetthepotentialforaworldwideenvironmentalcatastropheseemedsorealtohimfiveyearsagothathequithisjobandbecameafll﹣imevolunteerforanenvironmentalgroupthatworkedonrestoration恢复projects. SixmonthsintotheworkhedecidedthatAlkinson'sclasswasjustwhathewaslookingfor﹣﹣aplacewherehecoulddiscusshisconcernsaboutachangingclimate. Atkinsonsaidshehopestheclasshelpedherstudentspreparethemselvesfortheamountofenvironmentallossthatwillhappenovertheirlifetimes. Wearealreadychangingtheplanet﹣.somanyspeciesaregoingtobelostdisplacedormassivelyimpacted巨大影响的shesaid.Thefutureisn'tgoingtobewhattheyimagined. 1WhydidtheauthormentionthecaseofFawnSharp? A.TolayabasisforFawnSharp'sfurtherresearch. B.ToproveFawnSharp'sworkissimilartoAtkinson's. C.Toleadintotheissueoflosscausedbyclimatechange. D.Toshowscientists'concernabouttheMountAndersonglacier. 2What'sthemainpurposeofAtkinson'sclass? A.Toexplorehowdifferentpeopledealwithclimatechange. B.Togetstudentsmoreconcernedaboutenvironmentalissue. C.TofindsolutinstotheOlympicMountainsenvironmentalissue. D.Toteachstudentshowtoconductaresearchaboutenvironment. 3WhichofthefollowingbestexlainsintractableunderlinedinParagraphThree? A.Simple. B.Difficult. C.Common. D.Interesting. 4HowdidAtkinson'sclassinfluenceDillon? A.Dillonworkedasapart﹣timevolunteerforrestorationprojects. B.Itmadehimrealizeaplanet﹣wideclimatedisasterwouldhappen. C.Itencouragedhimtobemoreinvolvedinenvironmentalprotection. D.Itdiscouragedhimtoworkonrestorationprojectsfortheenvironment.
已知某几何体是由一个三棱柱和一个三棱锥组合而成的其三视图如图所示则该几何体的表面积为
设等差数列{an}的前n项和为Sn且a3+a5+a7=15则S9=
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设xy满足约束条件则z=x﹣2y的最小值是
已知等差数列{an}的前n项和为Sna3+a5=18S3+S5=50.数列{bn}为等比数列且b1=a13b2=a1a4. 1求数列{an}和{bn}的通项公式 2记其前n项和Tn证明.
已知圆Cx﹣32+y﹣42=1和两点A﹣m0Bm0m>0若圆上存在点P使得∠APB=90°则m的取值范围是.
若x=1是函数fx=x3+x2+ax+1的极值点则曲线y=fx在点0f0处的切线的斜率为
抛物线y2=2x上一点M到它的焦点F的距离为O为坐标原点则△MFO的面积为
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在平面直角坐标系xOy中曲线C1的参数方程为α为参数直线C2的方程为以O为极点以x轴非负半轴为极轴建立极坐标系. 1求曲线C1和直线C2的极坐标方程 2若直线C2与曲线C2交于PQ两点求|OP|•|OQ|的值.
七巧板是我国古代劳动人民的发明之一被誉为“东方模板”它是由五块等腰直角三角形一块正方形和一块平行四边形共七块板组成的.如图所示的是一个用七巧板拼成的正方形若在此正方形中任取一点则此点取自黑色部分的概率为
已知函数fx=xlnx﹣kx2﹣xab是函数x的两个极值点a<b. 1求k的取值范围 2证明a•b>e2.
6分KendickLamarhasn'thadmuchluckwhenitcomesiowningaGramy.Butthat'sOKTheUSrapper说唱歌手hasjustwonaPulitzerPrizeforhismusic. In2014in2016andagainthisyear.Lamarwasnominated提名foranalbumoftheyearGrammy.EachtimehewasbeatenoutfirstbyTaylorSwiftnextbyDaftPunkandmostrecentlybyBrunoMars. ButthePulitzePrizecommitteewasispiredcnoughbyLamar's2017albumDamn.toawardthe30﹣year﹣olditsPulizerPrizeinmusiconApril16.It'sanamazingalbumthatdocumentsthereallifeofmodemAfrican﹣AmericansinSouthLosAngeleswithwildlyaccomplishedbeatsandrhythms. Lamar'swinisconsideredtobehistorical.'ThePulizershavelongdisplayedtheirpreferencetowardhighartratherthanthepopcultureofthemasses.Soit'snotjustthatnorapperhaseverwonaPulitzernopopmusicmakerhaseverwononeintheaward's75﹣yearhistory. ButLamarisnotjustasinger一he'scleveratusinglanguage.Likethebestwritershismusicdescribessmallmomentsthatilustrate阐明largerpoints.HissongsareabouthisexperienceasablackmanwhogrewupinCalifomiastruggledgotintotroubleandfoundhiswayoutbyworkinghardandmakingsenseofthehistoryandrealityofracialproblemsintheUS. He'sanartistwhochallengesideasaidRyanCooglerdirectoreoftheblockbuste大片hitBlackPantherforwhichLamarcreatedmusic.Onebigthemeinourfimisthisideaof'WhatdoesitmeantobeAfrican?'Kendrickinhismusicisveryexactlyanddirectlychallengingthatquestion. Goodartistsentertainusgreataristsmakeusthinkandexceptionalaristshelpusempahize感同身受.Therearealotofgoodgreatevenexceptionalartistsinrockpopcountryandhip﹣hop.ButonlyLamarhasaPulizterPrize. 1WhatisLamarsalbumDamnabout? A.African﹣Americans'historyandculture. B.HardshipsoftheAfrican﹣Americanartists. C.ThewaystheUSgovemmentdealwithracialproblems. D.ThelivesofmodemblackpeopleinSouthLosAngeles. 2WhyisLamar'sPulitzerPrizewinsignificant? A.Heisthefirstfilm﹣makertowintheprize. B.Itisconsideredamilestoneforpopmusic. C.Heisthefirstblackpersontowintheprize. D.HehasmissedGrammyseveraltimesbefore. 3WhatcanwelearnfromRyanCoogler'swords? A.Lamardrewinspirationfromhisownexperience. B.Lamarhasthecouragetotakeonbigcallengesinlife. C.BlackPantheriswellknownbecauseofLamar'smusic. D.Lamar'smusicmathesthethemeofBlackPantherwell.
已知函数fxx∈R满足f﹣x=2﹣fx若函数y=sinπx+1与y=fx图象的交点为x1y1x2y2…xmym则xi+yi=
复数的Z=模为
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已知复数z=为纯虚数则实数a=
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若函数fx=m+sinx﹣cosx的最大值为0则m=
设椭圆=10>b>0的右顶点为A上顶点为B.已知椭圆的焦距为2直线AB的斜率为﹣.1求椭圆的标准方程2设直线ly=kxk<0与椭圆交于MN两点且点M在第二象限l与AB延长线交于点P若△BNP的面积是△BMN面积的3倍求k的值.
某学生5次考试的成绩单位分分别为8567m8093其中m>0若该学生在这5次考试中成绩的中位数为80则得分的平均数不可能为
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