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knew have known had known know
A11:D11 A5:D11 A5:A11:D5:D11 A5:A11
LOC(aij)=LOC(a11)+i×(i+1)/2+j LOC(aij)=LOC(a11)+i×(i+1)/2+(j-1) LOC(aij)=LOC(a11)+i×(i-1)/2+j LOC(aij)=LOC(a11)+i×(i-1)/2+(j-1)
Done That’s right Well done Not at a11
LOC(aij)=LOC(a11)+i×(i+1)/2+j LOC(aij)=LOC(a11)+i×(i+1)/2+(j-1) LOC(aij)=LOC(a11)+i×(i-1)/2+j LOC(aij)=LOC(a11)+i×(i-1)/2+(j-1)
建立一个A10连接 对A10连接周期性重注册 拆除A11连接 拆除A10连接
A3表达,A11不表达 A11表达,A3不表达 A3,A11同等表达 A3,A11相互抑制,都不表达 以上均不对
A3,A11同等表达 A3表达,A11不表达 A11表达,A3不表达 A3、A11互相抑制,都不表达 以上都不是
A3,A11同等表达 A3表达,A11不表达 A11表达,A3不表达 A3,A11相互抑制,都不表达 以上均不对
LOC(aij)=LOC(a11)+i×(i+1)/2+j LOC(aij)=LOC(a11)+i×(i+1)/2+(j-1) LOC(aij)=LOC(a11)+i×(i-1)/2+j LOC(aij)=LOC(a11)+i×(i-1)/2+(j-1)
LOC(ai=LOC(a11)+i×(i+1)/2+j LOC(ai=LOC(a11)+i×(i+1)/2+(j-1) LOC(ai=LOC(a11)+i×(i-1)/2+j LOC(ai=LOC(a11)+i×(i-1)/2+(j-1)
results from;lie in resuits in:lead to results in;lie in resuhs from:lead to