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N2H4+O2=N2+2H2O △H.= —534.4kJ/mol N2H4(g)+O2(g)=N2(g)+2H2O(g) △H. = —16.7kJ/mol N2H4(g)+O2(g)=N2(g)+2H2O(l) △H. = —534.4kJ/mol N2H4(g)+O2(g)=N2(g)+2H2O(g) △H. = —534.4kJ/mol
整个反应速度由第①步反应决定 正反应的活化能一定是①<② 该反应速率表达式:v=5000c2(NO)•c(H2) 该反应的热化学方程式为2NO(g)+2H2(g)═N2(g)+2H2O(g)△H=-664kJ•mol-1
2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g) ΔH=-542.7 kJ·mol-1 2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g) ΔH=-1059.3 kJ·mol-1 N2H4(g)+ N2O4(g)=N2(g)+2H2O(g) ΔH=-1076.7 kJ·mol-1 2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g) ΔH=-1076.7 kJ·mol-1
2N2H4(g) + 2NO2(g) = 3N2(g) + 4H2O(g); △H. = – 1135.7kJ/mol 2N2H4(g) + 2NO2(g) = 3N2(g) + 4H2O(g); △H. = – 1000.3kJ/mol N2H4(g) + NO2(g) = 3/2N2(g) + 2H2O(l); △H. = – 601.7kJ/mol 2N2H4(g) + 2NO2(g) = 3N2(g) + 4H2O(l); △H. = – 1135.7kJ/mol
2N2H4(g) + N2O4(g) = 3N2(g) + 4H2O(g) △H.=–1076.7 kJ/mol N2H4(g) + 1/2N2O4(g) =3/2N2(g) + 2H2O(g) △H.=–542.7 kJ/mol 2N2H4(g) + N2O4(g) = 3N2(g) + 4H2O(g) △H.=–542.7 kJ/mol 2N2H4(g) + N2O4(g) = 3N2(g) + 4H2O(l) △H.=–1059.3 kJ/mol
2△H和2K -2△H和 K2 2△H和-2K -2△H和 K-2
2N2H4(g)+N2O4(g)═3N2(g)+4H2O(g);△H=﹣542.7 kJ/mol 2N2H4(g)+N2O4(g)═3N2(g)+4H2O(g);△H=﹣1059.3 kJ/mol N2H4(g)+N2O4(g)═N2(g)+2H2O(g);△H=﹣1076.7 kJ/mol 2N2H4(g)+N2O4(g)═3N2(g)+4H2O(g);△H=﹣1076.7 kJ/mol
(k1ø)2*(k3ø)3*(k2ø)2 (k1ø)2*(k3ø)3/(k2ø)2 2(k1ø)+3(k3ø)-2(k2ø)2 (k1ø)2/(k3ø)3*(k2ø)2
减小压强 降低温度 增大O2浓度 使用合适的催化剂
2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g); △H.=-542.7kJ/mol 2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g); △H.=-1059.3kJ/mol 2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g); △H.=-1076.7kJ/mol N2H4(g)+1/2 N2O4(g)= 3/2N2(g)+2H2O(g);△H.=-1076.7kJ/mol
2N2H4(g)+N2O4(g)===3N2(g)+4H2O(g) ΔH.=-542.7 kJ/mol 2N2H4(g)+N2O4(g)===3N2(g)+4H2O(g) ΔH.=-1 059.3 kJ/mol 2N2H4(g)+N2O4(g)===3N2(g)+4H2O(g) ΔH.=-1 076.7 kJ/mol N2H4(g)+N2O4(g)===N2(g)+2H2O(g) ΔH.=-1 076.7 kJ/mol
N2H4(g)+2H2O2(l)= N2(g)+4H2O(l) ΔH.=+817.63 kJ·mol-1 N2H4(g)+2H2O2(l)= N2(g)+4H2O(g) ΔH.=-641.63 kJ·mol-1 N2H4(g)+2H2O2(l)= N2(g)+4H2O(l) ΔH.=-641.63 kJ·mol-1 N2H4(g)+2H2O2(l)= N2(g)+4H2O(g) ΔH.=-817.63 kJ·mol-1
减小压强 降低温度 增大O2浓度 使用合适的催化剂
2N2H4(g)+N2O4(g)===3N2(g)+4H2O(g) ΔH.=-542.7 kJ·mol-1 2N2H4(g)+N2O4(g)===3N2(g)+4H2O(g) ΔH.=-1 059.3 kJ·mol-1 2N2H4(g)+N2O4(g)===3N2(g)+4H2O(g) ΔH.=-1 076.7 kJ·mol-1 N2H4(g)+N2O4(g)===N2(g)+2H2O(g) ΔH.=-1 076.7 kJ·mol-1
2N2H4(g)+N2O4(g) ====3N2(g)+4H2O(g) ΔH=-542.7 kJ·mol-1 2N2H4(g)+N2O4(g) ====3N2(g)+4H2O(g) ΔH=-1 059.3 kJ·mol-1 N2H4(g)+1/2 N2O4(g) ====3/2N2(g)+2H2O(g) ΔH=-1 076.7 kJ·mol-1 2N2H4(g)+N2O4(g) ====3N2(g)+4H2O(g) ΔH=-1 076.7kJ·mol-1