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rxx=0.90 rxx=0.80 rxx=0 rxx=1.00
={x∈R.|x≥2}, ={x∈R.|x2-x-2<0}且R.为实数集,则下列结论正确的是( ) A.A.∪B.=R.B.A.∩B.≠Ø A.⊆(∁R.B.) A.⊇(∁R.B.)
={x∈R|0<x<3}, ={x∈R|x2≥4},则A.∩B=( ) A.{x|2<x<3}B.{x|2≤x<3} {x|x≤﹣2或2≤x<3} R.
rxx=0.90 rxx=0.80 rxx=0 rxx=1.00
(-∞,2] [1,2] [-2,2] [-2,1]
={x∈R|-2={x∈R|x<2},则A.∪(∁RB.)=( ) A.{x|x<6} B.{x|-2{x|x>-2} {x|2≤x<6}
={x∈R. ||x|≤2},B={x∈R. |x≤1},则A.∩ = ( ) A.(-∞,2] B.[1,2] [-2,2] [-2,1]
∀x∈R,x2+2x+3≠0 ∀x∈R,x2+2x+3=0 ∃x∈R,x2+2x+3≠0 ∃x∈R,x2+2x+3=0
={x∈R||x|≤2}, ={x∈R|x≤1},则A.∩B.=( ) A.(﹣∞,2]B.[1,2] [﹣2,2] [﹣2,1]
∀x∈R.,x<2 ∃x∈R.,x≤2 ∀x∈R.,x≤2 ∃x∈R.,x<2
rxx<0.70 0.70≤rxx<0.85 rxx≥0.85 rxx=1.00
∀x∈R,x<2 ∃x∈R,x≤2 ∀x∈R,x≤2 ∃x∈R,x<2
rxx<0.70 0.70≤rxx<0.85 rxx≥0.85 rxx=1.00
¬p:∃x∈R.,x2≥0 ¬p:∃x∈R.,x2<0 ¬p:∃x∈R.,x2≤0 ¬p:∀x∈R.,x2<0
rxx=0.90 rxx=0.80 rxx=0 rxx=1.00
47,XX(X,+21 46,XX(X,-14,+t(14q;2l 45,XX(X,-14,-2l,+t(14q;2l 46,XX(X,-21,+t(2l 46,XX(X,-22,+t(2lq;22