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如图,在△ABC中,AB=AC=2,∠B=40°,点D在线段BC上运动(D不与B、C重合),连结AD,作∠ADE=40°,DE交线段AC于E.(1)当∠BDA=115°时,∠BAD= ,∠DEC...
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如图所示在△ABC中∠ABC=∠ACB∠A.=40°点P.是△ABC内一点且∠1=∠2.则∠BPC=
在△ABC中AB=ACD是直线BC上一点不与点B.C重合以AD为一边在AD的右侧作△ADEAD=AE
如图△ABC中点O.是△ABC内一点且点O.到△ABC三边的距离相等.∠
=40°,则∠BOC=( )
A.110°
120°
130°
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CCBⅡ制动系统中B40是停放制动模块
如图在△ABC中AB=AC=2∠B.=40°点D.在线段BC上运动点D.不与B.C.两点重合连接AD
已知在△ABC中∠ABC=90°AB=3BC=4.点Q是线段AC上的一个动点过点Q作AC的垂线交线段
如图△ABC中点DE分别是ABAC的中点则下列结论①BC=2DE②△ADE∽△ABC③.其中正确的有
3个
2个
1个
0个
已知在△ABC中∠ABC=90°AB=3BC=4.点Q.是线段AC上的一个动点过点Q.作AC的垂线交
已知在△ABC中∠ABC=90°AB=3BC=4.点Q.是线段AC上的一个动点过点Q.作AC的垂线交
在△ABC中AB=AC点D.是直线BC上的一点不与点B.C.重合以AD为一边在AD的右侧作△ADE使
定义如图1点C在线段AB上若满足AC2=BC•AB则称点C为线段AB的黄金分割点.如图2△ABC中A
已知在△ABC中∠ABC=90°AB=3BC=4.点Q.是线段AC上的一个动点过点Q.作AC的垂线交
如图在△ABC中C.=90°AC=3BC=4将△ABC绕
逆时针旋转,使点C.落在线段AB上的点E.处,点
落在点D.处,则线段BE的长度为( ) A.2 B.3
4
2
如图将△ABC绕点
逆时针旋转100°,得到△ADE.若点D.在线段BC的延长线上,则∠
的大小为( )
A.30°B.40°
50°
60°
在△ABC中AB=AC点D.是射线CB上的一动点不与点B.C.重合以AD为一边在AD的右侧作△ADE
如图在△ABC中∠C.=40°将△ABC沿着直线l折叠点C.落在点D.的位置则∠1-∠2的度数是
40°
80°
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140°
已知在△ABC中∠ABC=90°AB=3BC=4点Q.是线段AC上的一个动点过点Q.作AC的垂线交线
在△ABC中已知2ABAC=3|AB||AC|=3BC2求角ABC的大小
如图所示在△ABC中∠ABC=∠ACB∠A.=40°P.是△ABC内一点且∠1=∠2.则∠BPC=_
如图甲在△ABC中∠ACB为锐角点D.为射线BC上一动点连接AD以AD为一边且在AD的右侧作正方形A
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