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已知:2H2(g)+O2(g)===2H2O(l) ΔH.=-571.6 kJ·mol-1 2CH3OH(l)+3O2(g)===2CO2(g)+4H2O(l...

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a<c<0         b>d>0   2a=b<0  2c=d>0  
已知2H2(g)+O2(g)===2H2O(g) ΔH.=-483.6 kJ· mol1说明2 mol H2(g)和1 mol O2(g)的能量总和小于2 mol H2O(g)的能量   已知  (s,石墨)===C(s,金刚石) ΔH.>0,则金刚石比石墨稳定 C.已知NaOH(aq)+HCl(aq)===NaCl(aq)+H2O(l) ΔH.=-57.4 kJ·mol1, 则含20 g NaOH的稀溶液与稀盐酸完全中和,放出28.7 kJ的热量   已知2C(s)+2O2(g)===2CO2(g) ΔH.1 2C(s)+O2(g)===2CO(g) ΔH.2,则ΔH.1>ΔH.2  
H2O(g) = H2(g) + 1/2 O2 (g) △H = +242 kJ/mol   2H2(g) + O2 (g) = 2H2O (l) △H = -484 kJ/mol   H2 (g) + 1/2 O2 (g) = H2O (g) △H = -242 kJ   2H2 (g) + O2 (g) = 2H2O (g) △H = +484 kJ/mol  
2C2H2(g) + 5O2(g) = 4CO2(g) + 2H2O(l) △H=-4b kJ/mol   C2H2(g) + 5/2O2(g) = 2CO2(g) + H2O(l) △H=2b kJ/mol   2C2H2(g) + 5O2(g) = 4CO2(g) + 2H2O(l) △H=-2b kJ/mol   2C2H2(g) + 5O2(g) = 4CO2(g) + 2H2O(l) △H=b kJ/mol  
2.43 kJ  4.86 kJ  43.8 kJ  87.5 kJ  
H2O(g)=H2(g)+1/2 O2(g) ΔH=+242 kJ/mol    2 H2(g)+O2(g)=2 H2O(g) ΔH=-484 kJ/mol    H2(g)+1/2 O2(g)=H2O(g) ΔH=+242 kJ/mol    2 H2(g)+O2(g)=2 H2O(g) ΔH=+484 kJ/mol  
a<c<0    b>d>0   2a=b<0    2c=d>0  
a<c<0     b>d>0  2a=b<0  2c=d>0  
H2O ( g ) = H2 ( g ) + 1/2O2 ( g ) △H = +242 kJ/mol   2H2 ( g ) + O2 ( g ) = 2H2O ( l ) △H = -484 kJ/mol   H2 ( g ) + 1/2O2 ( g ) = H2O ( g ) △H = +242 kJ/mol   2H2 ( g ) + O2 ( g ) = 2H2O ( g ) △H = +484 kJ/mol  
H2O ( g ) = H2 ( g ) + 1/2O2 ( g ) △H = +242 kJ/mol
  
2H2 ( g ) + O2 ( g ) = 2H2O ( l ) △H = -484 kJ/mol
  
H2 ( g ) + 1/2O2 ( g ) = H2O ( g ) △H = +242 kJ/mol
  
2H2 ( g ) + O2 ( g ) = 2H2O ( g ) △H = +484 kJ/mol
  
H2O(g)==H2(g) + 1/2O2(g);△H = - 242kJ/mol   2H2(g) + O2(g)==2HO(I);△H = - 484kJ/mol   2H2(g) + O2(g)==2H2O(g);△H = + 484kJ/mol   H2(g) + 1/2O2(g)==H2O(g);△H = - 242kJ/mol  
a<c<0    b>d>0    2a=b<0    2c=d>0  
a<b<0  b>d>0  2a=b<0   2c=d>0  
该反应原理可用于设计氢氧燃料电池   破坏1 mol H—O 键需要的能量是463.4 kJ   H2O(g)=H2(g) + 1/2O2(g) ΔH = +241.8 kJ/mol   H2(g) 中的H—H 键比 H2O(g) 中的H—O 键牢固  
-82kJ/mol   -41kJ/mol   -312kJ/mol   +82kJ/mol  
H2O(g)==H2(g)+1/2O2(g)       △H =-485 KJ.mol-1
   
H2O(g)==H2(g)+1/2O2(g)       △H = + 485 KJ.mol-1
   
2 H2(g) + O2(g)==2 H2O(g)     △H = + 485 KJ.mol-1
   
2 H2(g) + O2(g)==2 H2O(g)     △H =-485 KJ.mol-1  
H2O(g)=H2(g)+ 1/2O2 (g)△H=+242 kJ.mol-1    2H2(g)+O2(g)=2H2O(l) △H= -484 kJ.mol-l    H2(g)+ 1/2O2(g)=H2O(g) △H=+242 kJ.mol-l    2H2(g) + O2(g) = 2 H2O(g) △H= -484 kJ  

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