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a<c<0 b>d>0 2a=b<0 2c=d>0
已知2H2(g)+O2(g)===2H2O(g) ΔH.=-483.6 kJ· mol-1说明2 mol H2(g)和1 mol O2(g)的能量总和小于2 mol H2O(g)的能量 已知 (s,石墨)===C(s,金刚石) ΔH.>0,则金刚石比石墨稳定 C.已知NaOH(aq)+HCl(aq)===NaCl(aq)+H2O(l) ΔH.=-57.4 kJ·mol-1, 则含20 g NaOH的稀溶液与稀盐酸完全中和,放出28.7 kJ的热量 已知2C(s)+2O2(g)===2CO2(g) ΔH.1 2C(s)+O2(g)===2CO(g) ΔH.2,则ΔH.1>ΔH.2
H2O(g) = H2(g) + 1/2 O2 (g) △H = +242 kJ/mol 2H2(g) + O2 (g) = 2H2O (l) △H = -484 kJ/mol H2 (g) + 1/2 O2 (g) = H2O (g) △H = -242 kJ 2H2 (g) + O2 (g) = 2H2O (g) △H = +484 kJ/mol
2C2H2(g) + 5O2(g) = 4CO2(g) + 2H2O(l) △H=-4b kJ/mol C2H2(g) + 5/2O2(g) = 2CO2(g) + H2O(l) △H=2b kJ/mol 2C2H2(g) + 5O2(g) = 4CO2(g) + 2H2O(l) △H=-2b kJ/mol 2C2H2(g) + 5O2(g) = 4CO2(g) + 2H2O(l) △H=b kJ/mol
2.43 kJ 4.86 kJ 43.8 kJ 87.5 kJ
H2O(g)=H2(g)+1/2 O2(g) ΔH=+242 kJ/mol 2 H2(g)+O2(g)=2 H2O(g) ΔH=-484 kJ/mol H2(g)+1/2 O2(g)=H2O(g) ΔH=+242 kJ/mol 2 H2(g)+O2(g)=2 H2O(g) ΔH=+484 kJ/mol
a<c<0 b>d>0 2a=b<0 2c=d>0
a<c<0 b>d>0 2a=b<0 2c=d>0
H2O ( g ) = H2 ( g ) + 1/2O2 ( g ) △H = +242 kJ/mol 2H2 ( g ) + O2 ( g ) = 2H2O ( l ) △H = -484 kJ/mol H2 ( g ) + 1/2O2 ( g ) = H2O ( g ) △H = +242 kJ/mol 2H2 ( g ) + O2 ( g ) = 2H2O ( g ) △H = +484 kJ/mol
H2O ( g ) = H2 ( g ) + 1/2O2 ( g ) △H = +242 kJ/mol
2H2 ( g ) + O2 ( g ) = 2H2O ( l ) △H = -484 kJ/mol
H2 ( g ) + 1/2O2 ( g ) = H2O ( g ) △H = +242 kJ/mol
2H2 ( g ) + O2 ( g ) = 2H2O ( g ) △H = +484 kJ/mol
H2O(g)==H2(g) + 1/2O2(g);△H = - 242kJ/mol 2H2(g) + O2(g)==2H2O(I);△H = - 484kJ/mol 2H2(g) + O2(g)==2H2O(g);△H = + 484kJ/mol H2(g) + 1/2O2(g)==H2O(g);△H = - 242kJ/mol
a<c<0 b>d>0 2a=b<0 2c=d>0
a<b<0 b>d>0 2a=b<0 2c=d>0
该反应原理可用于设计氢氧燃料电池 破坏1 mol H—O 键需要的能量是463.4 kJ H2O(g)=H2(g) + 1/2O2(g) ΔH = +241.8 kJ/mol H2(g) 中的H—H 键比 H2O(g) 中的H—O 键牢固
-82kJ/mol -41kJ/mol -312kJ/mol +82kJ/mol
H2O(g)==H2(g)+1/2O2(g) △H =-485 KJ.mol-1
H2O(g)==H2(g)+1/2O2(g) △H = + 485 KJ.mol-1
2 H2(g) + O2(g)==2 H2O(g) △H = + 485 KJ.mol-1
2 H2(g) + O2(g)==2 H2O(g) △H =-485 KJ.mol-1
H2O(g)=H2(g)+ 1/2O2 (g)△H=+242 kJ.mol-1 2H2(g)+O2(g)=2H2O(l) △H= -484 kJ.mol-l H2(g)+ 1/2O2(g)=H2O(g) △H=+242 kJ.mol-l 2H2(g) + O2(g) = 2 H2O(g) △H= -484 kJ