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(-2,y1), (2,y2), (3,y3)都在反比例函数y=-的图象上, 则下列结论中正确的是 A.y1< y2< y3B.y3 < y2< y1C.y1< y3 < y2 y2 < y3 < y1
y3<y2<y1 y1<y2<y3 y2<y1<y3 y2<y3<y1
y=cy1(x)+y2(x) y=y1(x)+c2y2(x) y=c[y1(x)+y2(x)] y=c1y(x)-y2(x)
X1=0,X2=600,Y1=0,Y2=700 Y1=0,Y2=600,X1=0,X2=700 X1=0,X2=0,Y1=600,Y2=700 Y1=0,Y2=0,X1=600,X2=700
Abs(e^2*a+Log(y1^3)+Sin(y2)) Abs(Exp(2)*a+Log(y1^3)/Log(10)+Sin(y2)) Abs(e^2*a+lg(y1^3)+Sin(y2)) Abs(Exp(2)*a+Log(y1^3)+Sin(y2))
(-3,y1), (-2,y2), (-1,y3)三点都在函数y=-的图象上,则y1、y2、y3的大小关系是( ). A.y1>y2>y3 B.y1<y2<y3 C.y1=y2=y3 y1<y3<y2
fy2As2≤fy2As1 fy1As2≤fy1As1 fy2As2≥fy1As1 fy2As1≥fy2As2
(﹣2,y1), (3,y2)是反比例函数y=(k<0)图象上的两点,则有( ) A. y1<0<y2B. y2<0<y1 y1<y2<0 y2<y1<0
y2<y1<0 y1<y2<0 y2>y1>0 y1>y2>0
x1=2 y1=2 x2=2 y2=1 x1=2 y1=2 x2=2 y2=2 x1=2 y1=1 x2=2 y2=2 x1=2 y1=1 x2=2 y2=1
Abs(e^2*a+Log(y1^3)+Sin(y2)) Abs(Exp(2)*a+Log(y1^3)/Log(10)+Sin(y2)) Abs(e^2*a+lg(y1^3)+Sin(y2)) Abs(Exp(2)*a+Log(y1^3)+Sin(y2))
)y1 >y2 ( )y1 =y2 ( )y1 )不能比较