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已知椭圆C:=1(a>b>0)的离心率为,焦距为2. (1)求C的方程; (2)若斜率为﹣的直线与椭圆C交于P,Q两点(点P,Q均在第一象限),O为坐标原点,证明:直线OP,PQ,OQ的斜率依次...
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已知F.1F.2是椭圆a>b>0的两个焦点P.为椭圆短轴的端点且∠F.1PF2=90°则该椭圆的离心
已知椭圆的焦距为8离心率等于0.8求椭圆方程
,
,
,
或
,不确定
已知直线与椭圆相交于A.B两点.1若椭圆的离心率为焦距为2求线段AB的长2在1的椭圆中设椭圆的左焦点
已知椭圆的焦点在x轴上焦距是8离心率为0.8则椭圆的标准方程为______.
已知直线与椭圆相交于A.B.两点.1若椭圆的离心率为焦距为2求线段AB的长2在1的椭圆中设椭圆的左焦
已知椭圆的中心在原点焦点在y轴上若其离心率为焦距为8则该椭圆的方程是.
已知椭圆a>b>0的焦距为4且与椭圆有相同的离心率斜率为k的直线l经过点M.01与椭圆C.交于不同两
已知直线相交于A.B.两点1若椭圆的离心率为焦距为2求线段AB的长2若向量互相垂直其中O.为坐标原点
已知椭圆+=1a>0b>0的左焦点为F.右顶点为A.上顶点为B.若BF⊥BA则称其为优美椭圆那么优美
已知椭圆C的内接矩形面积的最大值为c为椭圆的半焦距长则椭圆C的离心率为.
离心率e=焦距为4的椭圆标准方程为______.
已知椭圆C.的中心在原点焦点在x轴上焦距为2离心率为.1求椭圆C.的方程2设直线l经过点M.01且与
已知椭圆的短轴大于焦距则它的离心率的取值范围是__________.
已知直线相交于A.B.两点1若椭圆的离心率为焦距为2求椭圆的标准方程2若其中O.为坐标原点当椭圆的离
椭圆Γ:+=1a>b>0的左右焦点分别为F.1F2焦距为2c.若直线y=x+c与椭圆Γ的一个交点满足
已知直线与椭圆相交于
,
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,焦距为2,则线段AB的长是( ) A.
B.
2
已知椭圆x2a2+y2b2=1a>b>0的右焦点为F右准线为l离心率e=55过顶点A0b作AM⊥l垂
已知离心率为的椭圆的中心在原点焦点在x轴上.双曲线以椭圆的长轴为实轴短轴为虚轴且焦距为2.求椭圆及双
已知椭圆的中心在原点焦点在y轴上若其离心率为焦距为8则该椭圆的方程是________.
已知直线相交于A.B.两点.若椭圆的离心率为焦距为2求线段AB的长2若向量互相垂直其中O.为坐标原点
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如图所示开关闭合后位于螺线管附近的小磁针N极指向下请在螺线管上画出导线的绕向.
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假设你是李华你的英国笔友Tony即将完成学业上周他来信就是否到中国工作询问你的意见.请根据以下提示回一封电子邮件内容包括 1建议他来中国就业; 2阐述你的理由就业机会多专业受欢迎不同的文化体验等; 3承诺可以提供帮助. 注意1词数100左右开头和结尾已给出不计入总词数; 2可适当增加细节以使行文连贯. DearTony Yours LiHua
小郑同学利用手边的器材天平和砝码空玻璃瓶足够的水某种液体顺利的完成了测量“某种液体密度”的实验.下面给出的是小郑完成实验时的第一个步骤请你将实验步骤补充完整.已知水的密度为ρ水待测液体足够多 1用调节好的天平和砝码测出空玻璃瓶的质量m0并记录在表格中 2用调节好的托盘天平测量并记录在表格中 3用调节好的托盘天平测量并记录在表格中 液体密度的计算公式ρ液=.
顶端优势现象产生的原因是
如图是标准大气压下质量为1g的某液体的体积﹣﹣温度图以下说法正确的是
我们可以用图示的电路图测量未知电阻RX的阻值.调节电路当电压表示数U为3.0V时电流表的示数为0.3A.如果考虑到电流表的电阻值RA为0.5Ω待测电阻RX′的阻值应为Ω.
手和脚有时会磨出“水泡”.“水泡”中的液体主要是
由金属杆组成如图所示的导轨其中水平面上两平行导轨足够长且全部置于竖直向上的磁场中与倾斜放置的导轨ABCD平滑且固定连接.将一金属棒ab从倾斜导轨上一定高度由静止释放运动过程中始终与导轨垂直接触且不受摩擦因为从能量转化的角度简述理由所以ab棒在水平导轨上的运动情况是选填加速减速或匀速.
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