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已知i为虚数单位,a为实数,复数z=(a﹣2i)(1+i)在复平面内对应的点为M,则“a=1”是“点M在第四象限”的( )
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高二上学期数学《》真题及答案
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已知z﹣2=z+2ii为虚数单位则复数z=
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2i
﹣2i
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已知i是虚数单位若复数z满足zi=1+i则z²=
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已知复数z1满足z1-21+i=1-ii为虚数单位复数z2的虚部为2z1·z2是实数求z2.
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已知复数z满足z-2i=1+ii为虚数单位则z的模为________.
2018年·哈六中二模已知复数z满足i﹣1z﹣i3=2ii为虚数单位则z的共轭复数为
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已知z是复数z+2i均为实数i为虚数单位且复数2+ai2在复平面上对应的点在第一象限求实数a的取值范
若复数z=x+i1+i是纯虚数其中x为实数i为虚数单位则z的共轭复数=.
若复数zl=-1+2iz2=-1-i其中i是虚数单位则zl+z2i的虚部为
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已知i为虚数单位1﹣2i•z=i3.则复数z在复平面内对应的点在
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已知复数z1满足z1-21+i=1-ii为虚数单位复数z2的虚部为2且z1·z2是实数求z2.
若复数z=1-im+2ii为虚数单位是纯虚数则实数m的值为.
已知复数z1满足z1-21+i=1-ii为虚数单位复数z2的虚部为2且z1·z2是实数则z2=.
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﹣3
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2i
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