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logab·logcb=logca logab·logca=logcb loga(bc)=logab·logac loga(b+c)=logab+logac
log32<log23<log25 log32<log25<log23 log23<log32<log25 log23<log25<log32
log0.440.46 1.013.4>1.013.5 3.50.3<3.40.3 log7667
loga(logax)ax2<(logax)2 loga(logax)< (logax)2< logax2 logax2a(logax)< (logax)2 (logax)2ax2a(logax)
log23.424.3 log67>log76 log0.23>log0.33 log3π0.3π
2 3 ﹣3