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甲、乙、丙三种物质的转化关系见下面如图所示,“→”表示反应可以一步实现(部分物质和反应条件已省略),下面选项中不能按图示转化关系实现的是( )
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某反应的微观示意图如图所示其中●表示汞原子○表示氧原子下列说法正确的是
图中甲.乙.丙三种物质中,甲.丙属于氧化物
图中甲.乙.丙三种物质均是由分子构成的
该反应前后分子种类.原子种类均没有改变
图中甲.乙.丙三种物质中既有单质又有化合物
甲乙丙是中常见的三种不同类型的物质其中乙是水它们之间的转化关系如图所示.→表示由一种物质转化成另一种
某反应的微观示意图如图所示其中●表示汞原子○表示氧原子下列说法正确的是
图中甲、乙、丙三种物质中,甲、丙属于氧化物
图中甲、乙、丙三种物质均是由分子构成的
该反应前后分子种类、原子种类均没有改变
图中甲、乙、丙三种物质中既有单质又有化合物
甲乙丙三种物质经一步反应的转化关系如图所示其中部分反应物生成物及反应条件已略去.1若甲和丙是无色液体
甲乙丙是常见的三种物质其相互转化关系如图所示甲为固态单质乙丙为元素组成相同的两种气体乙极易与血液中的
转化①②③可通过化合反应实现
转化②还可以通过置换反应实现
实现转化④时一定会放出热量
丙能产生温室效应
如图甲乙丙三种物质均含有地壳中含量最多的元素甲乙是组成元素完全相同的化合物丙是单质乙通常为液体在一定
现有甲乙丙三种金属采用将其中的一种金属分别放入另外两种金属的硫酸盐溶液中的方法进行实验得到三种金属间
乙、甲、丙
乙、丙、甲
丙、甲、乙
丙、乙、甲
甲乙丙三种物质的转化关系如右图所示→表示反应能一步实现部分反应物生成物和反应条件均已略去请回答下列问
现有甲乙丙三种金属采用将其中的一种金属分别放入另外两种金属的硫酸盐溶液中的方法进行实验得到三种金属间
乙、甲、丙
乙、丙、甲
丙、甲、乙
丙、乙、甲
甲乙丙是常见的三种物质在一定条件下它们之间的转换关系如图所示部分物质及反应条件均已略去其中甲乙是组成
甲乙丙是中常见的三种不同类型的物质其中乙是水它们之间的转化关系如图所示.→表示由一种物质转化成另一种
甲乙丙表示中常见的三种物质其中一种物质为单质另外两种物质的组成元素相同其转化关系如上图所示若甲为乙为
甲乙丙是常见的物质甲在一定条件下分解成乙和丙乙是最常用的氧化物.三种物质转化关系如图所示部分反应物生
甲乙丙三种物质经一步反应的转化关系如图所示其中部分反应物生成物及反应条件已略去.1若甲和丙是无色液体
甲乙丙是常见的三种物质甲乙为两种化合物且含有相同的元素丙为气体单质能使带火星的木条复燃它们之间有如图
甲乙丙三种物质之间的转化关系如图所示已知甲是常见的气体单质乙丙都只含有两种元素且组成元素相同回答下列
甲乙丙是中常见的三种不同类型的物质其中乙是水丙可以做助燃剂它们之间的转化关系如图所示.→表示由一种物
如图所示依据甲乙丙三种固体物质的溶解度曲线回答下列问题1t1℃时甲乙丙三种物质的溶解度的关系是用><
甲乙丙是常见的物质甲在一定条件下分解成乙和丙乙是最常用的氧化物.三种物质转化关系如图所示部分反应物生
如图甲乙丙三种物质均含有地壳中含量最多的元素甲乙是组成元素完全相同的化合物丙是单质乙通常为液体在一定
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某校为了开展“阳光体育运动”计划购买篮球足球共60个已知每个篮球的价格为70元每个足球的价格为80元. 1若购买这两类球的总金额为4600元求篮球足球各买了多少个 2若购买篮球的总金额不超过购买足球的总金额求最多可购买多少个篮球
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方程=1的解是
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一艘轮船在相距90千米的甲乙两地之间匀速航行从甲地到乙地顺流航行用6小时逆流航行比顺流航行多用4小时. 1求该轮船在静水中的速度和水流速度 2若在甲乙两地之间建立丙码头使该轮船从甲地到丙地和从乙地到丙地所用的航行时间相同问甲丙两地相距多少干米
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已知抛物线y=mx2和直线y=﹣x+b都经过点M﹣24点O为坐标原点点P为抛物线上的动点直线y=﹣x+b与x轴y轴分别交于AB两点. 1求mb的值 2当△PAM是以AM为底边的等腰三角形时求点P的坐标 3满足2的条件时求sin∠BOP的值.
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如图一次函数y=kx+b的图象与反比例函数y=的图象相交于AB两点其中点A的坐标为﹣14点B的坐标为4n. 1根据图象直接写出满足kx+b>的x的取值范围 2求这两个函数的表达式 3点P在线段AB上且S△AOPS△BOP=12求点P的坐标.
如图1在平面直角坐标系中抛物线y=x2+x﹣与x轴交于点AB点A在点B右侧点D为抛物线的顶点点C在y轴的正半轴上CD交x轴于点F△CAD绕点C顺时针旋转得到△CFE点A恰好旋转到点F连接BE. 1求点ABD的坐标 2求证四边形BFCE是平行四边形 3如图2过顶点D作DD1⊥x轴于点D1点P是抛物线上一动点过点P作PM⊥x轴点M为垂足使得△PAM与△DD1A相似不含全等. ①求出一个满足以上条件的点P的横坐标 ②直接回答这样的点P共有几个
求式子÷的值其中m=﹣2019.
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