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解方程:(30+x-20)(230-10x)=2520.
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教案备课库《初二年级(下)数学大练习(11)》真题及答案
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阅读下面的例题解方程解1当x≥0时原方程化为x2–x–2=0解得x1=2x2=-1不合题意舍去2当x
解方程30+x-20230-10x=2520.
阅读下列解方程组的方法然后解决有关问题.解方程组时我们如果直接考虑消元那是非常麻烦的而采用下面的解法
解方程. x﹣30%x=3.525%x+10x=40%x﹣20=140.
解方程2x2﹣4x﹣30=0.
解方程30%x=12+0.2x
解方程x+1x+2=xx-1
解方程19﹣120%x=730%x+0.5x=2.4x﹣60%x=0.161﹣20%x=0.32.
用配方法解方程x2+10x+20=0则方程可变形为
(x+5)
2
(x﹣5)
2
=45
(x+5)
2
=5
(x﹣5)
2
=5
解方程x﹣2=xx﹣2
小张在解方程5a-x=13时误将-x看作+x得到方程的解为x=-2则原方程的解为________.
解方程xx+12-xx2-3-2x+1x-1=20.
我们规定若关于x的一元一次方程ax=b的解为b﹣a则称该方程为差解方程例如2x=4的解为2且2=4﹣
解方程4x-320-x=6x-79-x
解方程320﹣x=6x﹣4x﹣11
解方程3x﹣5=20﹣2x.
下列解方程的过程中正确的是
x
2
=-2,解方程,得x=±
(x-2)
2
=4,解方程,得x-2=2,x=4
4(x-1)
2
=9,解方程,得4(x-1)=±3,x
1
=
,x
2
=
(2x+3)
2
=25,解方程,得2x+3=±5,x
1
=1,x
2
=-4
理解同解方程的定义再解题1同解方程的定义为如果两个方程的解相同那么这两个方程叫同解方程反之如果两个方
解方程xx﹣2=10x﹣20.
解方程x﹣1x﹣2=x+3x﹣4+20.
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