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x1=10,x2=2 x1=12,x2=10 x1=12,x2=2 x1:2,x2=2
X1 X2 (X1,X2) (X1,X2,X3,X4)
x1=10,x2=2 x1=12,x2=10 x1=12,x2=2 x1=2,x2=2
x1=10,x2=2 x1=12,x2=10 x1=12,x2=2 x1=2,x2=2
x1=10,x2=2 x1=12,x2=10 x1=12,x2=2 x1=2,x2=2
x1=10,x2=2 x1=12,x2=10 x1=12,x2=2 x1=2,x2=2
X1 X2 (X1,X2) (X1,X2,X3,X4)
若x≠0,则x+≥2 命题:若x2=1,则x=1或x=﹣1的逆否命题为:若x≠1且x≠﹣1,则x2≠1 “a=1”是“直线x﹣ay=0与直线x+ay=0互相垂直”的充要条件 若命题 :∃x∈R.,x2﹣x+1<0,则¬ :∀x∈R.,x2﹣x+1>0
x1=10,x2=2 x1=12,x2=10 x1=12,x2=2 x1=2,x2=2
x1=10,x2=2 x1=12,x2=10 x1=12,x2=2 x1=2,x2=2
x1=10,x2=2 x1=12,x2=10 x1=12,x2=2 x1=2,x2=2
x1=10,x2=2 x1=12,x2=10 x1=12,x2=2 x1=2,x2=2
A()A(int i)x1=i;void dispa()cout<<"x1="<<x1<<",";private: int x1; ; class B:public Apublic: B() B(int i):A(i+10)x2=i;void dispb()dispa(); cout<<"x2="<<x2<<endl;pnvate: int x2; ; int main()B b(2); b.dispb(); return 0;程序运行后的输出结果是( )。 x1=10,x2=2 x1=12,x2=10
X1 X2 (Xl,X2) (Xl,X2,X3,X4)
x1=10,x2=2 x1=12,x2=10 x1=12,x2=2 x1:2,x2=2