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化简:cos24°cos36°-cos66°cos54°
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高一下学期数学《2016级高一年级数学学科学案材料序号:453.1.1两角和与差的余弦公式》真题及答案
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cos24°cos36°﹣cos66°cos54°的值等于
0
﹣
化简=
cosα
﹣cosα
cos2α
﹣cos2α
化简=
cosα
﹣cosα
cos2α
﹣cos2α
cos24°cos36°﹣cos66°cos54°的值等于
0
﹣
求值sin6°sin42°cos24°cos12°=.
化简的结果是
-cos1
cos1
cos1
-
cos1
如图在Rt△ABO中斜边AB=1.若OC∥BA∠AOC=36°则
点
到AO的距离为sin54° B. 点B.到AO的距离为tan36°
点A.到OC的距离为sin36°sin54°
点A.到OC的距离为cos36°sin54°
观察①sin210°+cos240°+sin10°cos40°=②sin26°+cos236°+si
如图等腰△ABC中AB=AC∠BAC=36°BC=1点D.在边AC上且BD平分∠ABC设CD=x.1
如图在Rt△ABO中斜边AB=1若OC∥BA∠AOC=36°则
点
到AO的距离为sin54° B. 点B.到AO的距离为tan36°
点A.到OC的距离为sin36°sin54°
点A.到OC的距离为cos36°sin54°
已知函数fx=.若fsinα+sinβ+sin36°﹣1=﹣1fcosα+cosβ+cos36°+1
2
﹣
﹣2
如图在Rt△ABO中斜边AB=1.若OC∥BA∠AOC=36°则
点
到AO的距离为sin54° B.点B.到AO的距离为tan36°
点A.到OC的距离为sin36°sin54°
点A.到OC的距离为cos36°sin54°
化简sin2α+cos2αsin2β+cos2αcos2β=.
化简的结果是
sin4+cos4
sin4-cos4
cos4-sin4
-sin4-cos4
化简sin2π+α-cosπ+α·cos-α+1=.
比较大小sin24°cos66°.
化简sin2π+α-cosπ+αcos-α+1的值是________.
计算sin54°-xcos36°+x+cos54°-xsin36°+x.
化简的结果是
cos 160°
-cos 160°
±cos 160°
±|cos 160°|
化简+得到
2sin5
-2cos5
-2sin5
2cos5
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