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y+y″-4y′-4y=0 y+y″+4y′+4y=0 y-y″-4y′+4y=0 y-y″+4y′-4y=0
y3<y2<y1 y2<y3<y1 y1<y2<y3 y1<y3<y2
(-2,y1), (2,y2), (3,y3)都在反比例函数y=-的图象上, 则下列结论中正确的是 A.y1< y2< y3B.y3 < y2< y1C.y1< y3 < y2 y2 < y3 < y1
y3<y2<y1 y1<y2<y3 y2<y1<y3 y2<y3<y1
(x+4y)(x﹣4y) (x+2y)(x﹣2y) (x﹣4y)2 (x﹣2y)2
3-2y-1-4y=2 3(1-2y)-4y=2
3(2y-1)-4y=2 3-2y-4y=2
Abs(e^2*a+Log(y1^3)+Sin(y2)) Abs(Exp(2)*a+Log(y1^3)/Log(10)+Sin(y2)) Abs(e^2*a+lg(y1^3)+Sin(y2)) Abs(Exp(2)*a+Log(y1^3)+Sin(y2))
(-2,y1), (2,y2), (3,y3)都在反比例函数y=-的图象上, 则下列结论中正确的是 A.y1< y2< y3B.y3 < y2< y1C.y1< y3 < y2 y2 < y3 < y1
(-3,y1), (-2,y2), (-1,y3)三点都在函数y=-的图象上,则y1、y2、y3的大小关系是( ). A.y1>y2>y3 B.y1<y2<y3 C.y1=y2=y3 y1<y3<y2
(,y1)、 (,y2)、 (,y3)是该二次函数图象上的三点,则y1、 y2、 y3的大小关系是-----------------------------------------------( ) A.y2< y1< y3 B. y1< y2< y3 C. y3< y2< y1 y2< y3< y1
(﹣2,y1), (3,y2)是反比例函数y=(k<0)图象上的两点,则有( ) A. y1<0<y2B. y2<0<y1 y1<y2<0 y2<y1<0
Abs(e^2*a+Log(y1^3)+Sin(y2)) Abs(Exp(2)*a+Log(y1^3)/Log(10)+Sin(y2)) Abs(e^2*a+lg(y1^3)+Sin(y2)) Abs(Exp(2)*a+Log(y1^3)+Sin(y2))
(4x-3y)(-3y-4x) (2x2-y2)(2x2+y2) (a+b-c)(-c-b+a) (-x+y)(x-y)
)4x+y+3=0( )x+4y+3=0 ( )4x+y-3=0 ( )x ─4y─3=0
y'"+y"-4y'-4y=0. y'"+y"+4y'+4y=0. y'"-y"-4y'+4y=0. y'"-y"+4y'-4y=0.
)y1 >y2 ( )y1 =y2 ( )y1 )不能比较