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频率f=100Hz,初相角φ=-60°,则该电流的瞬时表达式为( )。i=10sin(200πt-60°)(A) i=7.07sin(100πt+30°)(A) i=5sin(100πt-60°)(A) i=7.07sin(100πt-30°)(A)
u=10sin(ωt-30°) u=14.14sin(ωt+30°) u=10sin(ωt+30°) u=sinωt
i1=I1sinωt,i2=I2sin(3ωt+60°),求i1+i2 u1=U1sin(ωt+45°),u2=U2sin(ωt-45°),求u1-u2 i1=I1sin(ωt+30°),i1=I2sin(3ωt-30°),求i1-i2 以上三式均可
u=100sin(50t+30) u=141.4sin(50t+30) u=200sin(100t+30) u=141.4sin(100t+30)
i=10sin(200πt-60°)(A) i=7.07sin(100πt+30°)(A) i=5sin(100πt-60°)(A) i=7.07sin(100πt-30°)(A)
100sin(50t+30°) 141.4sin(50πt) 200sin(100πt+30°) 200sin(50πt+30°)
100sin(50t+30°) 141.4sin(50πt) 200sin(100πt+30°) 200sin(50πt+30°)