单室模型静脉滴注给药的血药浓度随时间变化的关系式是.-X题卡

logX＝(－K/2.303)t＋logX₀ logC＝(－K/2.303)t＋logC₀ logC′＝(－K/2.303)t′＋log(K₀/VK) logC′＝(－K/2.303)t′＋log[K₀(1－e^－KT)/VK] C＝K₀(1－e^－KT)/KV

C＝C0（1-e-kt）/Vk logC’＝（-k/2.303）t’+log（k0/Vk） logC’＝（一k/2.303）t’+log（k0（1-e-kt）/Vk logC＝（一k/2.303）t+logC0 logX=（一k/2.303）t+logX0

A B C D E

logX＝(－K/2.303)t＋logX₀ logC＝(－K/2.303)t＋logC₀ logC′＝(－K/2.303)t′＋log(K₀/VK) logC′＝(－K/2.303)t′＋log[K₀(1－e^－KT)/VK] C＝K₀(1－e^－KT)/KV

logX＝(－K/2.303)t＋logX₀ logC＝(－K/2.303)t＋logC₀ logC′＝(－K/2.303)t′＋log(K₀/VK) logC′＝(－K/2.303)t′＋log[K₀(1－e^－KT)/VK] C＝K₀(1－e^－KT)/KV

C＝C₀(1-e^-kt)/Vk logC’＝(-k/2.303)t’+log(k₀/Vk) logC’＝(一k/2.303)t’+log(k₀(1-e^-kt)/Vk logC＝(一k/2.303)t+logC₀ logX=(一k/2.303)t+logX₀

A B C D E

logX=（-K/2.303）t+logX0 10gC=（-K/2.303）t+logC0 logC′=（-K/2.303）t′+log（K₀/V_K） 10gC′=（-K/2.303）t′+log[K₀（1-e-K_t）/V_K] C=K0（1-e-Kt）/K_V

logX=（-K/2.303）t+logX0 10gC=（-K/2.303）t+logC0 logC′=（-K/2.303）t′+log（K0/VK） 10gC′=（-K/2.303）t′+log[K0（1-e-KT）/VK] C=K0（1-e-Kt）/KV

logX＝(－K/2.303)t＋logX₀ logC＝(－K/2.303)t＋logC₀ logC′＝(－K/2.303)t′＋log(K₀/VK) logC′＝(－K/2.303)t′＋log[K₀(1－e^－KT)/VK] C＝K₀(1－e^－KT)/KV

C＝C0（1-e-kt）/Vk logC’＝（-k/2.303）t’+log（k0/Vk） logC’＝（一k/2.303）t’+log（k0（1-e-kt）/Vk logC＝（一k/2.303）t+logC0 logX=（一k/2.303）t+logX0

logX=（-K/2.303）t+logX0 10gC=（-K/2.303）t+logC0 logC′=（-K/2.303）t′+log（K0/VK） 10gC′=（-K/2.303）t′+log[K0（1-e-KT）/VK] C=K0（1-e-Kt）/KV

单室模型双室模型静脉注射给药等剂量、等间隔血管内给药静脉滴注给药

C＝C₀(1-e^-kt)/Vk logC’＝(-k/2.303)t’+log(k₀/Vk) logC’＝(一k/2.303)t’+log(k₀(1-e^-kt)/Vk logC＝(一k/2.303)t+logC₀ logX=(一k/2.303)t+logX₀

logX=（-K/2.303）t+logX0 10gC=（-K/2.303）t+logC0 logC′=（-K/2.303）t′+log（K₀/V_K） 10gC′=（-K/2.303）t′+log[K₀（1-e-K_t）/V_K] C=K0（1-e-Kt）/K_V

C=k₀(1－e^-kt)/VK logC’=(-k/2.303)t’＋log(k₀/VK) logC’=(-k/2.303)t’＋log[k₀(1－e^-kt)/VK] logC(-k/2.303)t＋logC₀ logX=(-k/2.303)t＋logX₀

C＝K₀(1-e^-kt)/VK logC’＝(-K/2.303)t’+log(K₀/VK) logC’＝(-K/2.303)t’+log(K₀(1-e^-KT)/VK) logC＝(-K/2.303)t+logC₀ logX＝(-K/2.303)t+logX₀

C＝K₀(1-e^-kt)/VK logC’＝(-K/2.303)t’+log(K₀/VK) logC’＝(-K/2.303)t’+log(K₀(1-e^-kt)/VK) logC＝(-K/2.303)t+logC₀ logX＝(-K/2.303)t+logX₀

C＝K₀(1-e^-kt)/VK logC’＝(-K/2.303)t’+log(K₀/VK) logC’＝(-K/2.303)t’+log(K₀(1-e^-KT)/VK) logC＝(-K/2.303)t+logC₀ logX＝(-K/2.303)t+logX₀

A B C D E

单室模型静脉滴注给药的血药浓度随时间变化的关系式是（）.