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拓展:如图1,在平行四边形ABCD中,对角线AC,BD相交于点O,过O点作直线EF,分别交BC,AD于点E、F:(1)证明:OF=OE;(2)小明从图1找到了一种将平行四边形面积平分的方法.图2是一...
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教案备课库《八(1)年级数学作业平行四边形的性质作业》真题及答案
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如图平行四边形ABCD的两条对角线AC与BD相交于点O.且AC⊥AB已知AC=10BD=26那么平行
如图平行四边形ABCD的两条对角线ACBD相交于点O.AB=5AC=6DB=8则四边形ABCD是的周
如图在四边形ABCD中对角线ACBD相交于点O.AE=CF且四边形DEBF是平行四边形.求证四边形A
在平行四边形ABCD中对角线AC和BD相交于点O.则下面条件能判定平行四边形ABCD是矩形的是
AC⊥BD
AC=BD
AC=BD且AC⊥BD
AB=AD
如图平行四边形ABCD的对角线ACBD交于点O.E.F在AC上G.H在BD上且AF=CEBH=DG.
在四边形ABCD中若两条对角线AC=BD且AC⊥BD则这个四边形[]
一定是正方形;
一定是菱形;
一定是平行四边形;
可能不是平行四边形.
如图所示已知平行四边形ABCD对角线ACBD相交于点O.∠BAO=∠DAO.1求证平行四边形ABCD
已知平行四边形ABCD对角线ACBD交于点O.1若AB=BC则平行四边形ABCD是_________
平行四边形ABCD中ACBD是两条对角线如果添加一个条件即可推出平行四边形ABCD是矩形那么这个条件
AB=BC
AC=BD
AC⊥BD
AB⊥BD
如图在平行四边形ABCD中对角线AC.BD相交于点O.F.E.是对角线AC上的两点当E.F.满足下列
OE=OF
DE=BF
∠ADE=∠CBF
∠ABE =∠CDF
如图平行四边形ABCD的两条对角线AC与BD相交于点O.且AC⊥AB已知AC=10BD=26那么平行
平行四边形ABCD中对角线AC与BD相交于OEF是AC上的两点并且AE=CE.求证四边形BFDE是
四边形ABCD中ACBD为对角线ACBD相交于点O.BO=4CO=6当AO=______DO=___
已知如图在四边形ABCD中AB∥CD对角线ACBD相交于点OBO=DO.求证四边形ABCD是平行四边
已知四边形ABCD是平行四边形对角线AC与BD相交于点O.那么下列结论中正确的是
)当AB=BC时,四边形ABCD是矩形; (
)当AC⊥BD时,四边形ABCD是矩形; (
)当OA=OB时,四边形ABCD是矩形; (
)当∠ABD=∠CBD时,四边形ABCD是矩形.
如图在四边形ABCD中对角线AC.BD相交于点O.若AO=CO=BO=DOAC⊥BD则四边形ABCD
平行四边形
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菱形
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