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要想在过程调用中返回两个结果,下面的过程定义语句合法的是( )。

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Sub Proc(x as Integer,y as Integer)  Sub Proc(ByVal x as Integer,y as Integer)  Sub Proc(x as Integer,ByVal y as Integer)  Sub Proc(ByVal x as Integer,ByVal y as Integer)  
Sub Submit(ByVal n,ByVal  Sub Submit(n,ByVal  Sub Submit(n,  Sub Submit(ByVal n,  
Sub Procl(n, m)  Sub Procl(ByVal n, m)  Sub Procl(n, ByVal m)  Sub Procl(ByVal n, ByVal m)  
Sub Proc1(n,m)  Sub Prod(ByVa1 n,m)  Sub Proc1(n,Byal m)  Sub Proc1(ByVal n,ByVal m)  
Sub P1(n,m)  Sub P1(ByVal n,m)  Sub P1(n,ByVal m)  Sub P1(ByVal n,ByVal m)  
Sub Proc(x as Integer,y as Integer)  Sub Proc(ByVal x as Integer,y as Integer)  Sub Proc(x as Integer,ByVal y as Integer)  Sub Proc(ByVal x as Integer,ByVal y as Integer)  
Sub Proc1(n,m)  Sub Proc1(By Val n ,m)  Sub Proc1(n, By Val m)  Sub Proc1 (By Val n,By Val m)  
Sub Submit(ByVal n,ByVal m)  Sub Submit(n,ByVal m)  Sub Submit(n,m)  Sub Submit(ByVal n,m)  
Sub Proc1(n,  Sub Proc1(By Valn,  Sub Proc1(n,ByVal  Sub Proc1(By Valn,By Val  
Sub Proc1(n,  Sub Proc1(ByVal n,  Sub Proc1(n,ByVa1  Sub Proc1(ByVa1 n,ByVa1  
Sub Procl(n,m)  Sub Procl(ByVal n,m)  Sub Procl(n,ByVal rn)  Sub Procl(ByVal n,ByVal m)  
Sub Proc1(n,m)  Sub Proc1(ByVal n,m)  Sub Proc1(n,BYVal m)  Sub Proc1(ByVal n,ByVal m)  
Sub Proc1(n,m)  Sub Proc1(ByVal n,m)  Sub Proc1(n,ByVa1 m)  Sub Proc1(ByVa1 n,ByVa1 m)  
Sub Proc(x as Integer, y as Intege  Sub Proc(By Val x as Integer, y as Intege  Sub Proc(x as Integer, By Val y as Intege  Sub Proc(By Val x as Integer, By Val y as Intege  
Sub Proc1(n,m)  Sub Proc1(By Valn,m)  Sub Proc1(n,ByVal m)  Sub Proc1(By Valn,By Val m)  
Sub Proc1(n,  Sub Proc1(By Val n ,  Sub Proc1(n, By Val  Sub Proc1 (By Val n,By Val  
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