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若函数f(x)=sinxcosx﹣cos2x+(x∈R)的图象上所有点纵坐标不变,横坐标伸长到原来的2倍,再向左平行移动个单位长度得函数y=g(x)的图象,则函数y=g(x)﹣在区间[﹣2π,4π]...
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高一下学期数学《》真题及答案
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函数fx=sinxcosx+cos2x的最小正周期和振幅分别是
π,1
π,2
2π,1
2π,2
已知函数fx=sin2x+2sinxcosx+3cos2xx∈R.求I求函数fx的最小正周期和单调递
下列函数中既是偶函数又在区间12内是增函数的为
y=cos2x,x∈R.
y=log
2
|x|,x∈R.且x≠0
y=
,x∈R.
y=x
3
+1,x∈R.
设函数fx=cos2x﹣﹣2sinxcosx.Ⅰ求fx的最小正周期并指出由fx的图象如何变换得到函数
函数fx=sinxcosx+cos2x的最小正周期和振幅分别是
π,1
π,2
2π,1
2π,2
函数fx=sinxcosx+cos2x的最小正周期和振幅分别是
π,1
π,2
2π,1
2π,2
已知函数fx=2sinxcosx+cos2x.Ⅰ求的值Ⅱ求函数fx的最大值及取得最大值时x的值
已知函数fx=-sin2x++6sinxcosx-2cos2x+1x∈R.I求fx的最小正周期II求
下列函数中既是偶函数又在区间12内是增函数的为
y=cos2x,x∈R.
y=log
2
|x|,x∈R.且x≠0
y=
,x∈R.
y=x
3
+1,x∈R.
对于任意x∈R.同时满足条件fx=f﹣x和fx﹣π=fx的函数是
f(x)=sinx
f(x)=sinxcosx
f(x)=cosx
f(x)=cos
2
x﹣sin
2
x
已知函数fx=2sinxcosx﹣cos2xx∈R..1求函数fx的单调递增区间2在△ABC中内角A
在下面给出的函数中哪一个函数既是区间上的增函数又是以π为周期的偶函数
y=x
2
(x∈R.)
y=|sinx|(x∈R.)
y=cos2x(x∈R.)
y=e
sin2x
(x∈R.)
函数fx=sinxcosx+cos2x的最小正周期和振幅分别是
π,1
π,2
2π,1
2π,2
已知函数fx=2sinxcosx+cos2xx∈R.1求fx的最小正周期和最大值2若θ为锐角且fθ+
已知函数fx=sin2x+2sinxcosx+3cos2xx∈R..求Ⅰ求函数fx的最小正周期和单调
设函数fx=sinxcosx-cosπ+xcosxx∈R.1求fx的最小正周期2若函数y=fx的图象
函数fx=cos2x﹣2sinxx∈R的值域为.
已知函数fx=cos4x﹣sin4x下列结论错误的是
f(x)=cos2x
函数f(x)的图象关于直线x=0对称
f(x)的最小正周期为π
f(x)的值域为[﹣
,
]
函数fx=sinx+cosx2+cos2x的最小正周期为.
函数y=cos2xx∈[0π]的增区间为.
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1已知tan求的值 2若且求sinβ的值.
sin=
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cos570°=
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