你可能感兴趣的试题
y=Acosω[t-(x-L)/u] y=Acosω[t-(x+L)/u] y=Acosω[t+(r+L)/u] y=Acosω[t+(x-L)/u]
y=Acosω[t-(x-L)/u] y=Acosω[t-(x+L)/u] y=Acosω[t+(x+L)/u] y=Acosω[t+(x-L)/u]
y=Acosω[t-(x0-x)/u]+φ0 y=Acosω[t-(x-x0)/u]+φ0 y=Acosωt-[(x0-x)/u]+φ0 y=Acosωt+[(x0-x)/u]+φ0
y=Acosω[t-(x0-x)/u]+φ0 y=Acosω[t-(x-x0)/u]+φ0 y=Acosωt-[(x0-x)/u]+φ0 y=Acosωt+[(x0-x)/u]+φ0
y=Acosω[t-(x-L)/u]+φ0 y=Acosω[t-(x/u)]+φ0 y=Acos[t-(x/u)] y=Acosω[t+(x-L)/u]+φ0
y=Acosπ[t-(x-5)/4] y=Acosπ[t-(x+5)/4] y=Acosπ[t+(x+5)/4] y=Acosπ[t+(x-5)/4]
y=Acosω[t-(x-L)/u] y=Acosω[t-(x+L)/u] y=Acosω[t+(x+L)/u] y=Acosω[t+(x-L)/u]
y=Acos(2πt/T-2πx/λ-1/2π) y=Acos(2πt/T+2πx/λ+1/2π) y=Acos(2πt/T+2πx/λ-1/2π) y=Acos(2πt/T-2πx/λ+1/2π)
y=Acosπ[t-(x-5)/4] y=Acosπ[t-(x+5)/4] y=Acosπ[t+(x+5)/4] y=Acosπ[t+(x-5)/4]
可以化简的,其化简顺序为P1→P2→P3 可以化简的,其化简顺序为P3→P1→P2 可以化简的,其化简顺序为P2→P1→P3 不可以化简的,因为P1、P2、P3申请的资源都不能得到满足
y=Acosπ[t-(x-5)/4] y=Acosπ[t-(x+5)/4] y=Acosπ[t+(x+5)/4] y=Acosπ[t+(x-5)/4]