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要想使23.78965421的输出为23.7887应用的语句是( )。

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outfilseekp(321,ios_base::cu;  outfilseekp(321,ios_base::be;  outfilseekp(-321,ios_ase::be;  outfilseekp(-321,ios_base::cu;  
OPEN(UNIT=3,FILE=‘QW’)  OPEN(3,FILE=QW)  OPEN(FILE=‘QW’,3,STATUS=OLD)  OPEN(3,FILE=QW,STATUS=UNKNOWN)  
outfilseekp(321,ios_base::cu;  outfilseekp(321,ios_base::bg;  outfilseekp(-321,ios_base::be;  outfilseekp(-321,ios_base::cu;  
cout < < 23.78965421;  cout < < fixed < < 23.78965421:  cout < < 23.78965421 -0.001:  cout < < fixed < < 23.78965421 -0.001;  
ch=Systeiread();  ch=(chaSysteiread();  ch=(chaSysteireadln();  ch=(inSysteiread();  
outfilseekp(321,ios_base::cu;  outfilseekp(321,ios_base::be;  outfilseekp(-321,ios_base::be;  outfilseekp(-321,ios_base::cu;  
ch= Systeiread();  ch=(chaSystcm iread();  ch=(chaSysteireadln();  ch=(inSystem iread();  
cout<<23.78965421;  cout<<fixed<<23.78965421;  cout<<23.78965421-0.001;  cout<<fixed<<23.78965421-0.001;  
outfilseekp (321, ios_ base:: cu;  outfilseekp (321,ios_ base:: be;  outfilseekp (-321,ios_ base:: be;  outfilseekp (-321,ios_ base:: cu;  
一个子类的两个父类中都有某个同名成员,在子类中对该成员访问可能出现二义性  解决二义性可以用对成员名的限定法  父类和子类中同时出现同名函数,也可能存在二义性  一个子类是从两个父类派生出来的,而这两个父类又有一个共同的父类,对该父类成员进行访问时,可能出现二义性  
cout < < 23.78965421;  cout < < fixed < < 23.78965421;  cout < < 23.78965421-0.001;  cout < < fixed < < 23.78965421-0.001;  

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