你可能感兴趣的试题
{﹣3,﹣2,﹣1,0} {﹣2,﹣1,0} {﹣3,﹣2,﹣1} {﹣2,﹣1}
={x1,x2,x3,x4},xi∈{﹣1,0,1},i={1,2,3,4},那么集合A.中满足条件“x12+x22+x32+x42≤3”的元素个数为( ) A.60 65 80 81
={x|x2﹣3x<0}, ={x|x2>4},则A.∩B.=( ) A.(﹣2,0)B.(﹣2,3) (0,2) (2,3)
={x|1={x|x2-2x-3≤0},则A.∩(∁R.B.)=( ) A.(1,4)B.(3,4) (1,3) (1,2)∪(3,4)
={x|1={x|x 2-2x-3≤0},则( ) A.(1,4)B.(3,4) (1,3) (1,2)U(3,4)
={x|x2-2x-3<0}, ={x|1≤x≤4},则A.∩B.= ( ) A.{x|1≤x<3} B.{x|1≤x≤3} {x|3{x|3≤x≤4}
={x||x-1|<2}, ={y|y=2x,x∈[0,2]},则A.∩B.= A.[1,3)B.(1,3) [0,2] (1,4)
={x||x-1|<2}, ={y|y=2x,x∈[0,2]},则A.∩B.= ( ) A.[0,2]B.(1,3) [1,3) (1,4)
={x||x-1|<2}, ={y|y=2x,x∈[0,2]},则A.∩B.=( ) A.[0,2]B.(1,3) [1,3) (1,4)
{x│0≤x<1} {x│0≤x<2} {x│0≤x≤1} {x│0≤x≤2}
={x|x2﹣(a+3)x+3a=0}, ={x|x2﹣5x+4=0},集合A.∪B.中所有元素之和为8,则实数a的取值集合为 ( ) A.{0}B.{0,3} {1,3,4} {0,1,3,4}
={x|x2-2x-3<0}, ={y|y=2x,x∈[0,2]},则A.∩B=( ) A.[0,2]B.(1,3) [1,3) (1,4)
,则实数a的取值范围为 ( ) A.[﹣1,2] [﹣1,2) [0,3) [0,3]
={x|1<x<4},集合B ={x|-2x-3≤0}, 则A.∩(CRB)= A. .(1,4) (3,4) (1,3) .(1,2)∪(3,4)
={(x1,x2,x3,x4,x5)|xi∈{-1,0,1},i=1,2,3,4,5},那么集合A.中满足条件“1≤|x1|+|x2|+|x3|+|x4|+|x5|≤3”的元素个数为( ) A.60 90 120 130
={x||x-1|≤2}, ={x|x2-4x>0,x∈R},则A.∩(CRB.)= ( ) A. [-1,3] B. [0,3] [-1,4] [0,4]
={x||x-1|<2}, ={y|y=2x,x∈[0,2]},则A.∩B.=( ) A.[0,2]B.(1,3) [1,3) (1,4)