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ab+ac+d=a(b+c)+d a2﹣1=(a+1)(a﹣1) 12ab2c=3ab•4bc (a+1)(a﹣1)=a2﹣1
(x+2)(x-2)=x2-4 x2-4y2=(x-2y)(x+2y) x2-4+3x=(x+2)(x-2)+3x 2a(b+c)-3(b+c)=2ab+2ac-3b-3c
a (x + y) =a x + a y x2-4x+4=x(x-4)+4 10x2-5x=5x(2x-1) x2-16+3x=(x-4)(x+4)+3x
(a+1)(a﹣1)=a2﹣1 (x﹣y)(m﹣n)=(y﹣x)(n﹣m) ab﹣a﹣b+1=(a﹣1)(b﹣1) m2﹣2m﹣3=m(m﹣2)﹣3
a(x+y)=ax+ay x2-4x+4=x(x-4)+4 10x2-5x=5x(2x-1) x2-16+6x=(x+4)(x-4)+6x
m(x﹣y)=mx﹣my x2+2x+1=x(x+2)+1 a2+1=a(a+) 15x2﹣3x=3x(5x﹣1)
(a+1)(a-1)=a2-1 a2-6a+9=(a-3)2 x2+2x+1=x(x+2x)+1 -18x4y3=-6x2y2·3x2y