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如图，平行四边形ABCD的对角线AC、BD，相交于点O，EF过点O且与AB、CD分别相交于点E、F，求证：AE＝CF．
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AC⊥BD
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∠ABE =∠CDF
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四边形ABCD中ACBD为对角线ACBD相交于点O.BO＝4CO＝6当AO＝______DO＝___
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菱形
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