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C=K0(1-e-kt)/VK logC’=(-K/2.303)t’+log(K0/VK) logC’=(-K/2.303)t’+log(K0(1-e-KT)/VK) logC=(-K/2.303)t+logC0 logX=(-K/2.303)t+logX0
C=C0(1-e-kt)/Vk logC’=(-k/2.303)t’+log(k0/Vk) logC’=(一k/2.303)t’+log(k0(1-e-kt)/Vk logC=(一k/2.303)t+logC0 logX=(一k/2.303)t+logX0
C=k0(1-e-kt)/Vk logC’=(-k/2.303)t’+log(k0/Vk) logC’=(-k/2.303)t’+log(k0(1-e-kt)/Vk logC=(-k/2.303)t+logC0 logX=(-k/2.303)t+logX0
单室模型 双室模型 静脉注射给药 等剂量、等间隔 血管内给药
C=K0(1-e-kt)/VK logC’=(-K/2.303)t’+log(K0/VK) logC’=(-K/2.303)t’+log(K0(1-e-KT)/VK) logC=(-K/2.303)t+logC0 logX=(-K/2.303)t+logX0
C=C0(1-e-kt)/Vk logC’=(-k/2.303)t’+log(k0/Vk) logC’=(一k/2.303)t’+log(k0(1-e-kt)/Vk logC=(一k/2.303)t+logC0 logX=(一k/2.303)t+logX0
单室模型静脉注射的药动学方程为:C=C0e-kt 单室模型药物静脉注射给药血药浓度的对数一时间图是一条直线 药物的生物半衰期与消除速率常数成正比 单室模型药物静脉注射给药,药物消除90%所需的时间为3.32 t1/2 药物的消除速度与该时刻体内的药物量成正比
C=k(1-e)/Vk logC′=(-k/2.303)t′+log(k/vk) logC′=(-k/2.303)t′+log[k(1-e)/Vk)] logC=(-k/2.303)t+logC logX=(一k/2.303)t+logX
单室模型 双室模型 静脉注射给药 等剂量、等间隔 血管内给药
-C=X0/VKT -C=FX0/VKT X20=X0/(1-e-kr) X20=C15V X=X0e-kr