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如图,在Rt△ABC中,∠ACB=90°,CD是AB边上的中线,AC=8,BC=6,则∠ACD的正切值是( )
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如图在Rt△ABC中∠ACB=90°AB=10CD是AB边上的中线则CD的长是【】
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.如图在Rt△ABC中∠ACB=90°∠
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如图在Rt△ACB中∠ACB=90°∠
=25°,点D.是AB上一点.将Rt△ABC沿CD折叠,使
点落在AC边上的点B.′处,则∠ADB′等于( )
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在Rt△ABC中∠ACB=90°AB=10CD是AB边上的中线则CD=.
如图在Rt△ABC中∠ACB=90°点D在AB边上将△CBD沿CD折叠使点B恰好落在AC边上的点E处
如图在Rt△ABC中∠ACB=90°CD是AB边上的中线DE⊥AB于点D.交AC于点E.求证∠AED
在Rt△ABC中∠ACB=90°CA=CB如果斜边AB=5cm那么斜边上的高CD=cm.
如图在Rt△ABC中∠ACB=90°点D.在AB边上将△CBD沿CD折叠使点B.恰好落在AC边上的点
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