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计算： sin45°-（sin60°-2cos30°）+tan30°
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教案备课库《八（1）数学组解直角三角形复习作业解直角三角形》真题及答案
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2cos30°+sin60°+2tan45°•tan60°.
函数Cos60°+ψ展开式为
Cos60° Cosψ +Sin60° Sinψ
Cos60° Cosψ -Sin60° Sinψ
Sin60° Cosψ -Cos60° Sinψ
Sin60° Cosψ +Cos60° Sinψ
2cos30°﹣|1﹣tan60°|+tan45°•sin45°.
Sin600tan300+︱sin450-1︱+tan600tan4500
sin2450+cos2450+tan300tan600+sin600cos300;
计算tan60°-cos45°·sin45°+sin30°
计算sin60°﹣4cos230°+sin45°•tan60°+﹣2.
sin
2
60°+cos
2
60°=1
sin30°+cos30°=1
sin60°=cos30°
tan45°＞sin45°
下列结论中正确的有①sin30°＋sin30°＝sin60°②sin45°＝cos45°③cos25
为锐角，且sinA.＝cos28°，则∠A.＝62°. A.1个
2个
3个
4个
求下列各式的值．2sin60°-2cos30°·sin45°．
tan260°－2cos30°－2sin45°=.
sin230°+cos245°+sin60°·tan45°
计算﹣1+sin60°﹣10﹣2cos30°+|﹣1|
计算cos45°－tan30°·sin60°.
观察下列等式①sin30°=cos60°=②sin45°=cos=45°=③sin60°=cos30
sin²60°+cos²60°=1
sin30°+cos30°=1
sin35°=cos55°
tan45°＞sin45°
sin230°+cos245°+sin60°·tan45°
计算tan60°+2sin45°-2cos30°的结果是___________.
计算sin45°-sin60°-2tan45°．
计算sin45°+sin60°-2cos45°
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