当前位置: X题卡 > 所有题目 > 题目详情

单室模型静脉滴注给药,体内血药浓度与时间的关系式为

查看本题答案

你可能感兴趣的试题

C=k0(1-e-kt)/VK  logC’=(-k/2.303)t’+log(k0/VK)  logC’=(-k/2.303)t’+log[k0(1-e-kt)/VK]  logC(-k/2.303)t+logC0  logX=(-k/2.303)t+logX0  
单室模型静脉注射给药,1gC对t作图,得到直线的斜率为负值  单室模型静脉滴注给药,在滴注开始时可以静注一个负荷剂量,使血药浓度迅速达到或接近稳态浓度  单室模型口服给药,在血药浓度达峰瞬间,吸收速度等于消除速度  多剂量给药、血药浓度波动与药物半衰期,给药间隔时间有关  多剂量给药、相同给药间隔下、半衰期短的药物容易蓄积  
logX=(-K/2.303)t+logX0   10gC=(-K/2.303)t+logC0   logC′=(-K/2.303)t′+log(K0/VK)   10gC′=(-K/2.303)t′+log[K0(1-e-KT)/VK]   C=K0(1-e-Kt)/KV  
C=K0(1-e-kt)/VK  logC’=(-K/2.303)t’+log(K0/VK)  logC’=(-K/2.303)t’+log(K0(1-e-KT)/VK)  logC=(-K/2.303)t+logC0  logX=(-K/2.303)t+logX0  
logX=(-K/2.303)t+logX0  10gC=(-K/2.303)t+logC0  logC′=(-K/2.303)t′+log(K0/VK)  10gC′=(-K/2.303)t′+log[K0(1-e-KT)/VK]  C=K0(1-e-Kt)/KV  
单室模型  双室模型  静脉注射给药  等剂量、等间隔  血管内给药  静脉滴注给药  
C=K0(1-e-kt)/VK  logC’=(-K/2.303)t’+log(K0/VK)  logC’=(-K/2.303)t’+log(K0(1-e-kt)/VK)  logC=(-K/2.303)t+logC0  logX=(-K/2.303)t+logX0  
logX=(-K/2.303)t+logX0  logC=(-K/2.303)t+logC0  logC′=(-K/2.303)t′+log(K0/VK)  logC′=(-K/2.303)t′+log[K0(1-e-KT)/VK]  C=K0(1-e-KT)/KV  
单室模型  双室模型  静脉注射给药  等剂量、等间隔  血管内给药  
C=K0(1-e-kt)/VK  logC’=(-K/2.303)t’+log(K0/VK)  logC’=(-K/2.303)t’+log(K0(1-e-KT)/VK)  logC=(-K/2.303)t+logC0  logX=(-K/2.303)t+logX0  
logX=(-K/2.303)t+logX0  logC=(-K/2.303)t+logC0  logC′=(-K/2.303)t′+log(K0/VK)  logC′=(-K/2.303)t′+log[K0(1-e-KT)/VK]  C=K0(1-e-KT)/KV  
单室模型  双室模型  静脉注射给药  等剂量、等间隔  血管内给药  
logX=(-K/2.303)t+logX0   10gC=(-K/2.303)t+logC0   logC′=(-K/2.303)t′+log(K0/VK)   10gC′=(-K/2.303)t′+log[K0(1-e-Kt)/VK]   C=K0(1-e-Kt)/KV  
C=K0(1-e-kt)/VK  logC’=(-K/2.303)t’+log(K0/VK)  logC’=(-K/2.303)t’+log(K0(1-e-kt)/VK)  logC=(-K/2.303)t+logC0  logX=(-K/2.303)t+logX0  

热门试题

更多