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(2a+b)2= .
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将a2+b2+2ab=a+b2改写成全称命题是
∃a,b∈R.,a
2
+b
2
+2ab=(a+b)
2
∃a<0,b>0,a
2
+b
2
+2ab=(a+b)
2
∀a>0,b>0,a
2
+b
2
+2ab=(a+b)
2
∀a,b∈R.,a
2
+b
2
+2ab=(a+b)
2
计算1-2ab22·3a2b-2ab-1
先化简再求值5a2b﹣2ab2+3ab﹣22ab﹣ab2其中a=﹣b=.
比较a2+b2与2ab的大小用><或=填空①当a=3b=2时a2+b22ab②当a=﹣1b=﹣1时a
先化简再求值4a³b+6ab³-2ab÷2ab其中a=-1b=2.
下列各式计算正确的是
a+2a
2
=3a
3
(a+b)
2
=a
2
+ab+b
2
2(a﹣b)=2a﹣2b
(2ab)
2
÷(ab)=2ab(ab≠0)
如果□×2ab=2a2b那么□内应填的代数式是„„„„„„„„„„„„„„
ab
2ab
a
2a
若ab=3a﹣2b=5则a2b﹣2ab2的值是
﹣3a2+2ab﹣4ab+2a2
假设某化学反应的反应过程如下图表示观察分析符合图中变化的化学反应为
A
2
+3B
2
2AB
3
2AB
2
+B
2
2AB
3
2A
2
B.+5B
2
==4AB
3
2AB
2
+B
2
==2AB
3
-2ab22·3a2b-2ab-1
已知a2+2ab=-10b2+2ab=16则a2+4ab+b2=_______a2-b2=_____
53a2b﹣2ab2﹣4﹣2ab2+3a2b
2ab5ab2+3a2b
与﹣2ab是同类项的为
﹣2ac
2ab
2
ab
﹣2abc
3a2-2ab--ab+b2
先化简再求值ab+a2﹣ab﹣a2﹣2ab其中a=1b=2.
4ab3﹣2ab÷2ab.
﹣3a2﹣4ab+[a2﹣22a2+2ab].
已知a2+2ab=﹣8b2+2ab=14则a2+4ab+b2=.
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