你可能感兴趣的试题
(*).data.a (*p).a p->data.a p.data.a
p=&data.n; *p=data.n; p=(struct sk*) &data.n; p=(struct sk*)data.n;
(*p).data.a (*p).a; p->data.a data.a
q=&data.m; *q=data.m; q=(struct sk*)&data.m; q=(struct sk*)data.m;
p=&datn; *p=datn; p=(struct sk*)&datn; p=(struct sk*)datn;
q=&data.m; *q=data.m; q=(struct sk*)&data. m; q=(struct sk*)data.m;
q=&data.m; *q=data.m; q=(struct sk*)&data.m; q=(struct sk*)data.m;
q=&datm; *q=datm; q=(struct sk*)&datm; q=(struct sk*)datm;
q=&datm; q=datm; q=(struct sk*)&datm; q=(struct sk*)datm;
p=&data.n; *p=data.n; p=(struct sk*)&data.n; p=(struct sk*)data.n;
(* .data (* .a; p->data data
q=&data.m; *q=data.m; q=(struct sk*)&data.m; q=(struct sk*)data.m;
(*p). data.a (*p). a; p->data. a data. a
P=&data.n; *P=data.n; P=(struct sk*)&data.n; P=(struct sk,)data.n;
q=&data.m; q=data.m; q=(struct sk*)&data.m; q=(struct sk*)data.m;
(*.data (*.a; p->data data
q=&datm; *q=datm; q=(struct sk*)&dat m; q=(struct sk*)datm;
p=(struct sk *)&data.a; p=(struct sk *)data.a; p=&data.a; *p=data.a;
q=&data.m; *q=data.m; q=(struct sk*)&data.m; q=(struct sk*)data.m;
p=&datn; *p=datn; p=(struct sk*)&datn; p=(struct sk*)datn: