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已知有结构体: struct sk int a; float b; data,*p; 若有p=&data,则对data的成员a的正确引用是()。

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p=&data.n; *p=data.n;  p=(struct sk*) &data.n; p=(struct sk*)data.n;  
(*p).data.a  (*p).a;  p->data.a  data.a  
q=&data.m;  *q=data.m;  q=(struct sk*)&data.m;  q=(struct sk*)data.m;  
p=&datn;  *p=datn;  p=(struct sk*)&datn;  p=(struct sk*)datn;  
q=&data.m;  *q=data.m;  q=(struct sk*)&data. m;  q=(struct sk*)data.m;  
q=&data.m;  *q=data.m;  q=(struct sk*)&data.m;  q=(struct sk*)data.m;  
q=&datm;  *q=datm;  q=(struct sk*)&datm;  q=(struct sk*)datm;  
q=&datm;  q=datm;  q=(struct sk*)&datm;  q=(struct sk*)datm;  
p=&data.n;  *p=data.n;  p=(struct sk*)&data.n;  p=(struct sk*)data.n;  
q=&data.m;  *q=data.m;  q=(struct sk*)&data.m;  q=(struct sk*)data.m;  
(*p). data.a  (*p). a;  p->data. a  data. a  
P=&data.n;  *P=data.n;  P=(struct sk*)&data.n;  P=(struct sk,)data.n;  
q=&data.m;  q=data.m;  q=(struct sk*)&data.m;  q=(struct sk*)data.m;  
(*.data  (*.a;  p->data  data  
q=&datm;  *q=datm;  q=(struct sk*)&dat m;  q=(struct sk*)datm;  
p=(struct sk *)&data.a;  p=(struct sk *)data.a;  p=&data.a;  *p=data.a;  
q=&data.m;  *q=data.m;  q=(struct sk*)&data.m;  q=(struct sk*)data.m;  
p=&datn;  *p=datn;  p=(struct sk*)&datn;  p=(struct sk*)datn:  

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