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-82kJ/mol -41kJ/mol -312kJ/mol +82kJ/mol
升高温度 将容器的体积缩小一半 增加C.的量 降低温度
H2(g) CO(g) C.8H18(l) CH4(g)
由反应①、②可知如图所示的热化学方程式为CO(g)+H2O(g)==== CO2(g)+H2(g)ΔH = -41.2 kJ·mol-1 H2的燃烧热为241.8 kJ·mol-1 H2(g)转变成H2O(g)的化学反应一定要释放能量 根据②推知反应H2(g)+1/2O2(g)==== H2O(l)ΔH > -241.8 kJ·mol-1
C.+ H2O == CO + H2 ∆H= +131.3 kJ mol H -1 C(s)+ H2O(g) == CO(g) + H2(g) ∆H= +10.94 kJ·mol -1 C(s)+ H2O(l) == CO(g) + H2(g) ∆H= +131.3 kJ· mol -1 C(s)+ H2O(g) == CO(g) + H2(g)∆H= +131.3 kJ· mol -1
2H2(g) + O2(g)= 2H2O(g) △H1 ; 2H2(g) + O2(g) = 2H2O(l) △H2 S(g) + O2(g) =SO2(g) △H1 ; S(s) + O2(g) = SO2(g) △H2 CO(g) + 1/2 O2(g) = CO2(g) △H1 ;2CO(g) + O2(g) = 2CO2(g) △H2 C.(s)+H2O(g)=CO(g)+H2(g) △H1 ;CaO(s)+H2O(l)===Ca(OH)2(s) △H2
C+H2O=CO+H2 ΔH = +10.9 kJ/ mol C(s)+H2O(g)=CO(g)+H2(g) ΔH = +10.94 kJ/ mol C(s)+H2O(g)=CO(g)+H2(g) ΔH = +131.28 kJ/ mol 1/2C(s)+ 1/2H2O(g)= 1/2CO(g)+ 1/2H2(g ) ΔH = + 65.64 kJ/ mol
0.5 mol CO+2 mol H2O(g)+1 mol CO2+1 mol H2 1 mol CO+1 mol H2O(g)+1 mol CO2+1 mol H2 0.5 mol CO+1.5 mol H2O(g)+0.4 mol CO2+0.4 mol H2 0.5 mol CO+1.5 mol H2O(g)+0.5 mol CO2+0.5 mol H2